Find the equation of the circle whose centre is (3, 4) and which touches the line 5x + 12y = 1.
6 views
0 votes
0 votes
Find the equation of the circle whose centre is (3, 4) and which touches the line 5x + 12y = 1.
by
2.2k points

1 Answer

0 votes
0 votes
 
Best Answer

Solution:

Let r be the radius of the circle. Then

r = distance of the centre i.e. point (3, 4) from the line 5x + 12y = 1

Hence the required equation of the circle is

by
2.2k points

Related questions

S. Ruby Asked Feb 11, 2023
2 views
S. Ruby Asked Feb 11, 2023
by S. Ruby
7.8k points
1 answer
0 votes
0 votes
2 views
S. Ruby Asked Feb 11, 2023
5 views
S. Ruby Asked Feb 11, 2023
by S. Ruby
7.8k points
1 answer
0 votes
0 votes
5 views
1 answer
0 votes
0 votes
4 views
1 answer
0 votes
0 votes
5 views
1 answer
0 votes
0 votes
6 views
WELCOME TO ANSWER AVENUE, WHERE YOU CAN ASK QUESTIONS AND RECEIVE ANSWERS FROM OTHER MEMBERS OF THE COMMUNITY.

Categories