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 A storage battery of emf 8.0 V and internal resistance

0.5

is being

charged by a 120 V DC supply using a series resistor of

15.5

. What is

the terminal voltage of the battery during charging? What is the purpose

of having a series resistor in the charging circuit?

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Ans: In the above question it is given that:

Emf of the storage battery is

E 0.8V  .

Internal resistance of the battery is

r 0.5   .

DC supply voltage is

V 120V 

Resistance of the resistor is

R 15.5  .

Consider effective voltage in the circuit to be

V'.

V' V E   V' 120 8 112V   

Now current flowing in the circuit is

I

and the resistance

R

is connected in

series to the storage battery.

Therefore, using Ohm’s law,

V' I

R r

112 I 7A

15.5 0.5

  

Hence voltage across resistor

R

will be:

IR 7 15.5 108.5V   

DC supply voltage = Terminal voltage of battery + Voltage drop across

R

Terminal voltage of battery

   120 108.5 11.5V

A series resistor in a charging circuit is responsible for limiting the current

drawn from the external source. The current will be extremely high in its

absence which is very dangerous.

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